30 6.2 Autoionisation of Water
Practice questions
- Does hydrogen ion concentration [latex]\ce{H^{+}}[/latex] remain constant in all aqueous solutions?
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- No, hydrogen ion concentration varies with the amount of water present in an aqueous solution.
- Yes, hydrogen ion concentration remains constant in all aqueous solutions because of the amount of water.
- Yes, because [latex]\ce{H^{+} {\times} OH^{-} = 1.0 {\times} 10^{-14}}[/latex]
- No, hydrogen ion concentration varies with the amount of acid or base present in an aqueous solution.
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- For a given aqueous solution, if [latex]\ce{{[H^{+}]}=1.0{\times}10^{-3}M}[/latex], what is [latex]\ce{[OH^{-}]}[/latex]?
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- [latex]\ce{1.0{\times}10^{-11}}[/latex]
- [latex]\ce{1.0{\times}10^{-6}}[/latex]
- [latex]\ce{1.0{\times}10^{-17}}[/latex]
- [latex]\ce{1.0{\times}10^{-14}}[/latex]
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- For a given aqueous solution, if [latex]\ce{{[H^{+}]} = 7.92{\times}10^{-5}M}[/latex], what is [latex]\ce{[OH^{-}]}[/latex]?
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- [latex]\ce{0.89{\times}10^{-10}M}[/latex]
- [latex]\ce{1.26{\times}10^{-10}M}[/latex]
- [latex]\ce{1.26{\times}10^{-9}M}[/latex]
- [latex]\ce{1.26{\times}10^{-19}M}[/latex]
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- For a given aqueous solution, if [latex]\ce{{[OH^{-}]}=1.0{\times}10^{-5}M}[/latex], what is [latex]\ce{H^{+}}[/latex]?
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- [latex]\ce{5.0{\times}10^{-9}M}[/latex]
- [latex]\ce{1.0{\times}10^{-6}M}[/latex]
- [latex]\ce{1.0{\times}10^{-9}M}[/latex]
- [latex]\ce{2.5{\times}10^{-9}M}[/latex]
- [latex]\ce{1.0{\times}10^{-14}M}[/latex]
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- For a given aqueous solution, if [latex]\ce{{[OH^{-}]} = 3.77{\times}10^{-4}M}[/latex], what is [latex]\ce{H^{+}}[/latex]?
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- [latex]\ce{2.65{\times}10^{-10}M}[/latex]
- [latex]\ce{0.65{\times}10^{-12}M}[/latex]
- [latex]\ce{2.65{\times}10^{-11}M}[/latex]
- [latex]\ce{1.0{\times}10^{-11}M}[/latex]
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- What are [latex]\ce{[H^{+}]}[/latex] and [latex]\ce{[OH^{-}]}[/latex] in a [latex]\ce{0.344M}[/latex] solution of [latex]\ce{HNO_{3}}[/latex]?
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- [latex]\ce{{[H^{+}]}=0.657M}[/latex] and [latex]\ce{{[OH^{-}]}=0.91{\times}10^{-10}M}[/latex]
- [latex]\ce{{[H^{+}]}1.0{\times}10^{-10}M}[/latex] and [latex]\ce{{[OH^{-}]}=1.0{\times}10^{-14}M}[/latex]
- [latex]\ce{{[H^{+}]}=5.0{\times}10^{-12}M}[/latex] and [latex]\ce{{[OH^{-}]}=2.5{\times}10^{-14}M}[/latex]
- [latex]\ce{{[H^{+}]}=0.344M}[/latex] and [latex]\ce{{[OH^{-}]}=2.91{\times}10^{-14}M}[/latex]
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- What are [latex]\ce{[H^{+}]}[/latex] and [latex]\ce{[OH^{-}]}[/latex] in a [latex]\ce{0.00338M}[/latex] solution of [latex]\ce{KOH}[/latex]?
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- [latex]\ce{{[H^{+}]}=2.96{\times}10^{-12}M}[/latex] and [latex]\ce{{[OH^{-}]}=0.00338M}[/latex]
- [latex]\ce{{[H^{+}]}=0.00338M}[/latex] and [latex]\ce{{[OH^{-}]}=1.56{\times}10^{-12}M}[/latex]
- [latex]\ce{{[H^{+}]}=0.96{\times}10^{-12}M}[/latex] and [latex]\ce{{[OH^{-}]}=1{\times}10^{-8}M}[/latex]
- [latex]\ce{{[H^{+}]}=0.96{\times}10^{-12}M}[/latex] and [latex]\ce{{[OH^{-}]}=1{\times}10^{-10}M}[/latex]
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- If [latex]\ce{HNO_{2}}[/latex] is dissociated only to an extent of [latex]\ce{0.445%}[/latex], what are [latex]\ce{[H^{+}]}[/latex] and [latex]\ce{[OH^{-}]}[/latex] in a [latex]\ce{0.307M}[/latex] solution of [latex]\ce{HNO_{2}}[/latex]?
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- [latex]\ce{{[H^{+}]}=0.00137M}[/latex] and [latex]\ce{{[OH^{-}]}=0.78{\times}10^{-10}M}[/latex]
- [latex]\ce{{[H^{+}]}=0.137M}[/latex] and [latex]\ce{{[OH^{-}]}=0.32{\times}10^{-10}M}[/latex]
- [latex]\ce{{[H^{+}]}=1.37{\times}10^{-12}M}[/latex] and [latex]\ce{{[OH^{-}]}=7.32{\times}10^{-12}M}[/latex]
- [latex]\ce{{[H^{+}]}=0.00137M}[/latex] and [latex]\ce{{[OH^{-}]}=7.32{\times}10^{-12}M}[/latex]
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Answers
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- d
- a
- b
- c
- c
- d
- a
- d